Integrand size = 19, antiderivative size = 112 \[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=-\frac {\sqrt {a x^2+b x^3}}{3 x^4}-\frac {b \sqrt {a x^2+b x^3}}{12 a x^3}+\frac {b^2 \sqrt {a x^2+b x^3}}{8 a^2 x^2}-\frac {b^3 \text {arctanh}\left (\frac {\sqrt {a} x}{\sqrt {a x^2+b x^3}}\right )}{8 a^{5/2}} \]
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Time = 0.09 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {2045, 2050, 2033, 212} \[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=-\frac {b^3 \text {arctanh}\left (\frac {\sqrt {a} x}{\sqrt {a x^2+b x^3}}\right )}{8 a^{5/2}}+\frac {b^2 \sqrt {a x^2+b x^3}}{8 a^2 x^2}-\frac {b \sqrt {a x^2+b x^3}}{12 a x^3}-\frac {\sqrt {a x^2+b x^3}}{3 x^4} \]
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Rule 212
Rule 2033
Rule 2045
Rule 2050
Rubi steps \begin{align*} \text {integral}& = -\frac {\sqrt {a x^2+b x^3}}{3 x^4}+\frac {1}{6} b \int \frac {1}{x^2 \sqrt {a x^2+b x^3}} \, dx \\ & = -\frac {\sqrt {a x^2+b x^3}}{3 x^4}-\frac {b \sqrt {a x^2+b x^3}}{12 a x^3}-\frac {b^2 \int \frac {1}{x \sqrt {a x^2+b x^3}} \, dx}{8 a} \\ & = -\frac {\sqrt {a x^2+b x^3}}{3 x^4}-\frac {b \sqrt {a x^2+b x^3}}{12 a x^3}+\frac {b^2 \sqrt {a x^2+b x^3}}{8 a^2 x^2}+\frac {b^3 \int \frac {1}{\sqrt {a x^2+b x^3}} \, dx}{16 a^2} \\ & = -\frac {\sqrt {a x^2+b x^3}}{3 x^4}-\frac {b \sqrt {a x^2+b x^3}}{12 a x^3}+\frac {b^2 \sqrt {a x^2+b x^3}}{8 a^2 x^2}-\frac {b^3 \text {Subst}\left (\int \frac {1}{1-a x^2} \, dx,x,\frac {x}{\sqrt {a x^2+b x^3}}\right )}{8 a^2} \\ & = -\frac {\sqrt {a x^2+b x^3}}{3 x^4}-\frac {b \sqrt {a x^2+b x^3}}{12 a x^3}+\frac {b^2 \sqrt {a x^2+b x^3}}{8 a^2 x^2}-\frac {b^3 \tanh ^{-1}\left (\frac {\sqrt {a} x}{\sqrt {a x^2+b x^3}}\right )}{8 a^{5/2}} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.83 \[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=-\frac {\sqrt {x^2 (a+b x)} \left (\sqrt {a} \sqrt {a+b x} \left (8 a^2+2 a b x-3 b^2 x^2\right )+3 b^3 x^3 \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )\right )}{24 a^{5/2} x^4 \sqrt {a+b x}} \]
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Time = 2.00 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.64
method | result | size |
pseudoelliptic | \(-\frac {5 \left (-\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right ) b^{4} x^{4}+\sqrt {b x +a}\, \left (\sqrt {a}\, b^{3} x^{3}-\frac {2 a^{\frac {3}{2}} b^{2} x^{2}}{3}+\frac {8 a^{\frac {5}{2}} b x}{15}+\frac {16 a^{\frac {7}{2}}}{5}\right )\right )}{64 a^{\frac {7}{2}} x^{4}}\) | \(72\) |
risch | \(-\frac {\left (-3 b^{2} x^{2}+2 a b x +8 a^{2}\right ) \sqrt {x^{2} \left (b x +a \right )}}{24 x^{4} a^{2}}-\frac {b^{3} \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right ) \sqrt {x^{2} \left (b x +a \right )}}{8 a^{\frac {5}{2}} x \sqrt {b x +a}}\) | \(81\) |
default | \(\frac {\sqrt {b \,x^{3}+a \,x^{2}}\, \left (3 \left (b x +a \right )^{\frac {5}{2}} a^{\frac {5}{2}}-8 \left (b x +a \right )^{\frac {3}{2}} a^{\frac {7}{2}}-3 \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right ) a^{2} b^{3} x^{3}-3 \sqrt {b x +a}\, a^{\frac {9}{2}}\right )}{24 x^{4} \sqrt {b x +a}\, a^{\frac {9}{2}}}\) | \(89\) |
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Time = 0.27 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.56 \[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=\left [\frac {3 \, \sqrt {a} b^{3} x^{4} \log \left (\frac {b x^{2} + 2 \, a x - 2 \, \sqrt {b x^{3} + a x^{2}} \sqrt {a}}{x^{2}}\right ) + 2 \, {\left (3 \, a b^{2} x^{2} - 2 \, a^{2} b x - 8 \, a^{3}\right )} \sqrt {b x^{3} + a x^{2}}}{48 \, a^{3} x^{4}}, \frac {3 \, \sqrt {-a} b^{3} x^{4} \arctan \left (\frac {\sqrt {b x^{3} + a x^{2}} \sqrt {-a}}{a x}\right ) + {\left (3 \, a b^{2} x^{2} - 2 \, a^{2} b x - 8 \, a^{3}\right )} \sqrt {b x^{3} + a x^{2}}}{24 \, a^{3} x^{4}}\right ] \]
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\[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=\int \frac {\sqrt {x^{2} \left (a + b x\right )}}{x^{5}}\, dx \]
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\[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=\int { \frac {\sqrt {b x^{3} + a x^{2}}}{x^{5}} \,d x } \]
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Time = 0.32 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.82 \[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=\frac {\frac {3 \, b^{4} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right ) \mathrm {sgn}\left (x\right )}{\sqrt {-a} a^{2}} + \frac {3 \, {\left (b x + a\right )}^{\frac {5}{2}} b^{4} \mathrm {sgn}\left (x\right ) - 8 \, {\left (b x + a\right )}^{\frac {3}{2}} a b^{4} \mathrm {sgn}\left (x\right ) - 3 \, \sqrt {b x + a} a^{2} b^{4} \mathrm {sgn}\left (x\right )}{a^{2} b^{3} x^{3}}}{24 \, b} \]
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Timed out. \[ \int \frac {\sqrt {a x^2+b x^3}}{x^5} \, dx=\int \frac {\sqrt {b\,x^3+a\,x^2}}{x^5} \,d x \]
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